In ΔOPQ, q = 6.5 inches, o = 8.6 inches and ∠P=55°. Find ∠Q, to the nearest 10th of an degree.

∠Q = 35.5°

Step-by-step explanation:

We are given;

q = 6.5 inches

o = 8.6 inches

∠P = 55°

Let's first use cosine rule to find p.

p² = q² + o² - 2qo cos P

Plugging in the relevant values;

p² = 6.5² + 8.6² - (2 × 6.5 × 8.6 × cos 55)

p² = 42.25 + 73.96 - 32.0629

p² = 84.1471

p = √84.1471

p = 9.17 inches

Using sine rule, we can find ∠Q;

p/sin P = q/sin Q

sin Q = (q•sinP)/p

sin Q = (6.5 × sin 55)/9.17

sin Q = 0.5806

Q = sin^(-1) 0.5806

Q ≈ 35.5°

47.5  

Step-by-step explanation:

From delta math

answer: ur mum is gay

the given 6 = w/p is equivalent to 6p = w, where w is the total area of the walls and p is the area covered by a single can of paint.

knowing that 6 cans of paint will be needed, 6p = w becomes 6(6) = w = 36.   this tells us that the total area to be painted is 36 square units.