If p(x)=(x-1)(x+1), then find the value of p(2)+p(1)-p(0)​

2

Step-by-step explanation:

Given data

We have the function p(x)=(x-1)(x+1)

Let us find

p(2), p(1), and p(0)

p(2)= (2-1)(2+1)

p(2)= (1)(3)

p(2)= 3

P(1)= (1-1)(1+1)

p(1)= 0*1

P(1)= 0

p(0)= (0-1)(0+1)

p(0)= 1

Hence , p(2)+p(1)-p(0)​

=3+0-1

=3-1

=2

12.5 feet

step-by-step explanation:

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb