A number card numbered from 1 to 30 is drawn randomly.
What is the
probability of getting
a card having
the number divisible by 6 or 7?​

3/10

Step-by-step explanation:

We have to list out the numbers that are divisible by 6 and 7 that we can find between 1 and 30

so, we have this as;

6,7,12,14,18, 21, 24,28 and 30

The count we have here is 9

The total number we have is 30

So the probability is simply the count we have divided by 30

so we have this as ; 9/30 =

3/10

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

answer: b)

step-by-step explanation:

its a dot plot because since the score is not high numbers.

- r3ktforgood ☕