The circles with the centre at P and Q are such that each passes through the centre of the other. the circle intersect at points R and S as shown what is the measure of ∠PRQ

a.45⁰
b.50⁰
c.60⁰
d.90⁰​

C) 60°

Step-by-step explanation:

Each side of the triangle is a radius of the circle.  Since all three sides are equal, it’s an equilateral triangle, so they are all 60° angles.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.