What is the midpoint of (6,3) and (-3,-7)​

(Xm, Ym) = [ x1+x2/2, y1 + y2/2]

Given (6,3) (-3,-7)

x1 y1 x2 y2

Step-by-step explanation:

(Xm,Ym) =[ 6-3/2, 3-7/4]

= [ 3/2, -1]

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18