PLEASE HELP! ITS URGENT In American football, the ball is punted by dropping and kicking it before it hits the ground. The height h (t) of the football above the ground in meters t seconds after being punted is affected by gravity and by the punter’s kick, and can be represented as the difference of two functions: a (t) = 4.9t^2, which specifies the effect of gravity on the height of the ball, and v(t)=13.7t+0.5, which specifies the effect of the punt on the ball. With these two functions, h(t) = v(t) - a(t), how high above the ground was the ball when it was punted?

h = 8.845 m

The height h(t) of the football above the ground in meters t seconds after being punted is affected by gravity and by the punters kick, and can be represented as the difference of two functions:

We need to find h(t) such that, h(t)=v(t)-a(t)

So,

It is a quadratic equation. When we solve it we get :

Neglecting negative value,

h(t) = 8.845 m

So, the ball was at a height of 8.845 m when it was punted.

I think this is correct and if not lmk and i can make a post and give fr33 p01nts

he kicked it up? is this the answer ?

step-by-step explanation:

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: