Find the tangent line equation of the curve at the given point. Y=arcsin(7x) at the point where x=sqrt2/14

Step-by-step explanation:

The equation of the curve is

To find the equation of tangent we need to differentiate this equation w.r.t x

So, differentiating we get

This would give the slope of the tangent line at any given point of which x coordinate is known. In the present case it is  

Then slope would accordingly be

= ∞

For, ,

Equation of tangent line, in the point slope form, would be

true

step-by-step explanation:

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6