In 2011, the moose population in a park was measured to be 5,700. By 2018, the population was measured again to be 9,400. If the population continues to change exponentially, find an equation for the moose
population, P, as a function of t, the years since 2011.
Round numbers to 3 decimal places as needed.
What does your model from above predict the moose population to be in 2023?
Round your answer to the nearest whole moose.

P = 5700(1.074ⁿ)

13,437 moose in 2023    13,425 if you use the rounded function above.

Step-by-step explanation:

p = 5700(1 + x)ⁿ

n = years elapsed     x = percentage increase per year

2018 - 2011 = 7 years

9400 = 5700(1 + x)⁷

9400/5700 = (1 + x)⁷

ln(9400/5700) = 7ln(1 + x)

ln(9400/5700) / 7 = ln(1 + x)

e^(ln(9400/5700) / 7) = e^(ln(1 + x))

1.07407879 = 1 + x

x = 0.07407879

2023 - 2011 = 12

P = 5700(1.074¹²) = 13,437

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068