A person invested \$5,600$5,600 in an account growing at a rate allowing the money to double every 6 years. How long, to the nearest tenth of a year would it take for the value of the account to reach \$72,500$72,500?

22.2 years

Step-by-step explanation:

Doubling formula is given as:

P(t) = Po × (2)^t/k

Where

Po = Initial amount invested = $5600

P(t) = Amount after time t = $72500

k = Time it takes to double = 6 years

t = Time in years = ??

Hence:

72500 = 5600 × (2)^t/6

Divide both sides by 5600

72500/5600 =( 5600 × (2)^t/6)5600

12.946428571 = (2)^t/6

Take the In of both sides

In 12.946428571 = In (2)^t/6

In 12.946428571 = t/6 In (2)

Divide both sides by In 2

In 12.946428571/In 2 = t/6

3.6944822628 = t/6

Cross Multiply

t = 6 × 3.6944822628

t = 22.166893577 years

Approximately

t = 22.2 years

Therefore, it would take 22.2 years

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

1; 35 is the ratio

step-by-step explanation: