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Solve the equation for x.3(6x - 1) = 12 i've tried doing the math and i can't find out what i'm doing wrong
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What value is a discontinuity of x squared plus 8 x plus 4, all over x squared minus x minus 6?
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Simplify each expression. use positive exponents. show work . (x β2 y β4 x 3 ) β2
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