Adrian, bobby, and chandler are assigned a random order during a three-person batting competition. What is the probability that bobby is assigned to go first, chandler is assigned to go second and Adrian is assigned to go last.

1/6

Step-by-step explanation:

The process of each individual getting chosen is a sequence of events, meaning we need to multiply each individual probability separately in order to get the probability of this happening. For the first choice, the probability is 1/3 since there can only be one chosen to go first and there are three options. For the second choic,e the probability is 1/2 because only one can be chosen but there are now only 2 options since someone got chosen to be first. This leaves the last probability which is 1/1 since only one person is left. Therefore, to get the probability of this event happening we need to multiply all of these probabilities together...

1/3 * 1/2 * 1/1 = x

Therefore the probability of Bobby going first, Chandler going second, and Adrian going last is 1/6

the answer is simply just 6n add the two together as they have an n