A survey of Lakeview High School students found that 72% of the students had eaten breakfast that morning. If two students are chosen at random from a group of 100 students, what is the probability that at least one of them did not eat breakfast that morning?

4.26 * 10^-12

Step-by-step explanation:

Usibg the binomial probability relation :

P(x =x) = nCx * p^x * q^(n-x)

Probability of success = probability of not eating = 1 - 0.72 = 0.28

p = 0.28

q = 1 - p = 0.72

Probability that atleast one out of 2 chosen did not eat breakfast :

P(x ≥ 1) = p(x = 1) + p(x = 2)

P(x ≥ 1) = (100C1 * 0.28^1 * 0.72^99) + (100C2 * 0.28^2 * 0.72^98)

= 4.26 * 10^-12

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column