A company produces packets of soap powder labeled "Giant size 32 Ounces." The actual weight of soap powder in a box has a normal distribution with a mean of 33 oz. And a standard deviation of 0.8 oz. The proportion of packets that are underweight (i. E. Weight less than 32 oz.) are

0.1057

Step-by-step explanation:

We solve the above question using z score formula

z = (x-μ)/σ, where

x is the raw score = 32 oz

μ is the population mean = 33 oz

σ is the population standard deviation = 0.8oz

For x < 32 oz

z = 32 - 33/0.8

z = -1.25

Probability value from Z-Table:

P(x<32) = 0.10565

Approximately = 0.1057

Therefore, the proportion of packets that are underweight (i.e. Weight less than 32 oz.) are 0.1057.

1 1/7 hope i

step-by-step explanation:

8/7 = (1 * 7 + 1) / 7 = 1 + 1/7 = 1 1/7