Given a scalar field 6 .
2 V  x y z  y Evaluate the line integral
V dr
c

along the curve c having
parametric equations
x 2t 3, y. t and z 3t
2
   
between points M(3, 0, 0) and N(5, 1, 3).

answer: idk

step-by-step explanation:

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !

i need points

step-by-step explanation: