WILL GIVE BRAINLIEST Q1) The coordinates of 3 the vertices of a parallelogram ABCD are A (-4,3), B (5,-5), and C (15,-1).
a) Find the coordinates of the point of intersection of the diagonals.
b) Find the coordinates of the point D.
c) Find the area of parallelogram ABCD.?

Let coordinates of vertex D be (x,y)

In parallelogram diagonals are bisect each other.

∴ Mid-point of AC= Mid-point of BD

⇒ (

2

3+(−6)

,

2

−4+2

)=(

2

−1+x

,

2

−3+y

)

⇒ (

2

−3

,

2

−2

)=(

2

−1+x

,

2

−3+y

)

⇒ (

2

−3

,−1)=(

2

−1+x

,

2

−3+y

)

Now,

⇒

2

−3

=

2

−1+x

⇒ −6=−2+2x

⇒ −4=2x

∴ x=−2

⇒ −1=

2

−3+y

⇒ −2=−3+y

⇒ 1=y

∴ y=1

∴ Coordinates of vertex D is (−2,1)

i think the correct option is the second option.

you are uyytr tyy

step-by-step explanation: