A quantity with an initial value of 110 grows continuously at a rate of 0.5% per hour. What is the value of the quantity after 6 hours, to the nearest hundredth?

113.35

Step-by-step explanation:

Write a function:

f(t)=110e^{rt}

r: grows 0.5%→0.005

f(t)=110e^0.005t

(where t is in hours)

6 hours: no time conversion necessary

Plug in t=6

f(6)=110e^{0.005(6)}

113.349998735

=113.35

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

the olimpics is not going to wokk out

step-by-step explanation: