Define a relation Q on the set Rx R as follows. For all ordered pairs (w, x) and (y, z) in RxR, (w, x) Q (y, z) = x= z. (a) Prove that is an equivalence relation. To prove that is an equivalence relation, it is necessary to show that is reflexive, symmetric, and transitive. Proof that Q is an equivalence relation: (1) Proof that Q is reflexive: Construct a proof by selecting sentences from the following scrambled list and putting them in the correct order.
a. By the reflexive property of equality, x = x
b. By definition of Q, (w, x) = (w, x).
c. By the symmetric property of equality, w = w.
d. By the reflexive property of equality, w = w.
e. By the symmetric property of equality, x = x.

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step-by-step explanation:

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4