Two fair number cubes are rolled. The table below shows the possible outcomes for each number cube and their sum. + 1 2 3 4 5 6
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12

What is the theoretical probability of rolling two numbers with a sum less than 6?

The easiest method is to draw a possibility space first. The grid shows the totals for two dice. There are: 6×6=36 possible outcomes. Of these there are 10 totals which are less than 6.

Step-by-step explanation:

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6/36  or 1/6 either answer is correct. but you must show your workings for 6/36

Step-by-step explanation:

We look at the data within each line that shows 1,2,3,4,5,6 both horizontal shows match with vertical.

We count 10 possible outcomes that would show product of under  6 out of 36 events = 6/36

If it asks to simplify we see 6 divides into 6 and 36 = 1/6

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2