For what values of x is the expression below defined?
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x > 0

Step-by-step explanation:

Given :-

And we need to find the value of x for which the expression is defined . The expression is ,

√[3x²] ÷ √[4x]

As we can see that x is inside the squareroot. So for defining the expression the value of x should be Greater than 0 . As negative inside the squareroot will give rise to imaginary numbers.

Solution :-

x > 0

In interval notation :-

Therefore x should be Greater than 0 .

i pretty sure it is