A research study comparing three treatments with n= 5 in each treatment produces T1= 5, T2= 10, T3= 15, with SS1= 6, SS2= 9, SS3=9, and EX= 94. For this study, what is SSbetween

SSbetween is 10

Step-by-step explanation:

Given the data in the question;

A research study comparing three treatments with n = 5 in each treatment produce;

that is: n₁ = 5, n₂ = 5, n₃ = 5

T₁ = 5, T₂ = 10, T₃ = 15,

SS₁ = 6, SS₂ = 9, SS₃ = 9

∑x² = 94

First, we obtain the grand total;

G = T₁ + T₂ + T₃ = 5 + 10 + 15 = 30

N = n₁ + n₂ + n₃ = 5 + 5 + 5 = 15

Total SS =  ∑x² - ( G²/N )

we substitute

Total SS =  94 - ( (30)²/ 15 )

Total SS =  94 - ( 900 / 15 )

Total SS =  94 - 60

Total SS =  34

To get the SSbetween or Between SS;

Between SS = ∑( T²/n ) - ( G²/N )

Between SS = ∑( (5)²/5 + (10)²/5 + (15)²/5 ) - ( (30)²/ 15 )

Between SS = ∑( 25/5 + 100/5 + 225/5 ) - ( 900 / 15 )

Between SS = ∑( 5 + 20 + 45 ) - 60

Between SS = 70 - 60

Between SS = 10

Therefore, SSbetween is 10

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0