A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
y=-16x^2+129x+119
y=β16x Β
2
+129x+119
answered: Guest
(1/x + 1)^2 + 6 (1/x + 1) +5
answered: Guest
answer: none of these answers are correct only the second half is