2. The pointer of a spinner with 3 congruent sectors is spun once and a tetrahedron labelled 1 to 4 is rolled
R
1
The table shows the possible outcomes.
Tetrahedron
1
2
3
R
R/1
R/3
R/A
R/2
G/2
Spinner G
G/1
G/3
G/4
B/4
В B
B/1
B/2
B/3
Find the probability of cach cvent:
a) the pointer landing on red
P(red) = 12
HINI
Howy
Odlcomes erede
Flow may
outcomes have a 3
b) rolling a 3
P(3) = 1
12
c) red and a 3
P(R/3) =
Compare the probability in parte) with the product of the probabilities in parts a) and b).
What do you notice?​

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step-by-step explanation:

ddd

step-by-step explanation:

step-by-step explanation:

to find if any function is an inverse of the other, put the first equation in as x in the next one. then simplify and solve. if at the end you get the statement y = x, then it is an inverse. if you get anything else, it is not.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)