Mathematics, 19.05.2021 21:00, shaonaworld
In ΔJKL, k = 4.4 inches, l = 8.6 inches and ∠J=129°. Find the length of j, to the nearest 10th of an inch.
Answers: 1
Mathematics, 21.06.2019 16:00, Destinationz
Svetlana's hair is 4 4 centimeters ( cm cm) long. her hair grows 1 . 5 cm 1.5cm per month. svetlana wants her hair to be less than 1 6 cm 16cm long. write an inequality to determine the number of months, m m, svetlana can allow her hair to grow so that it is less than 1 6 cm 16cm long.
Answers: 3
Mathematics, 21.06.2019 17:50, tiffcarina69
F(x) = x2 − 9, and g(x) = x − 3 f(x) = x2 − 4x + 3, and g(x) = x − 3 f(x) = x2 + 4x − 5, and g(x) = x − 1 f(x) = x2 − 16, and g(x) = x − 4 h(x) = x + 5 arrowright h(x) = x + 3 arrowright h(x) = x + 4 arrowright h(x) = x − 1 arrowright
Answers: 2
Mathematics, 21.06.2019 18:50, hartmaaj95
The first few steps in solving the quadratic equation 9x2 + 49x = 22 ? 5x by completing the square are shown. 9x2 + 49x = 22 ? 5x 9x2 + 54x = 22 9(x2 + 6x) = 22 which is the best step to do next to solve the equation by completing the square? 9(x2 + 6x + 3) = 25 9(x2 + 6x + 3) = 49 9(x2 + 6x + 9) = 31 9(x2 + 6x + 9) = 103
Answers: 3
Mathematics, 21.06.2019 19:40, evarod
Afactory makes propeller drive shafts for ships. a quality assurance engineer at the factory needs to estimate the true mean length of the shafts. she randomly selects four drive shafts made at the factory, measures their lengths, and finds their sample mean to be 1000 mm. the lengths are known to follow a normal distribution whose standard deviation is 2 mm. calculate a 95% confidence interval for the true mean length of the shafts. input your answers for the margin of error, lower bound, and upper bound.
Answers: 3
In ΔJKL, k = 4.4 inches, l = 8.6 inches and ∠J=129°. Find the length of j, to the nearest 10th of an...
Mathematics, 02.10.2019 23:00
Mathematics, 02.10.2019 23:00
Mathematics, 02.10.2019 23:00