Hey can i get some advice for middle school :)

Calculate the monthly payment for a $2,500 loan at 9% annual interest for two years. use the formula, m = pm(1 + m)^na/(1 + m)^na - 1 as needed. a. $85.15 b. $105.40 c. $114.21 d. $125.72 calculate the total payback for a $2,500 loan at 9% annual interest for two years. use the formula, m = pm(1 + m)^na/(1 + m)^na - 1 as needed. a. $1,021.80 b. $1,370.52 c. $2,043.60 d. $2,741.04 alice wants to use the stack method to pay down her debts listed in the table below. if she applies an extra $150 a month to her debts, what will be the second debt she targets to pay off and what will be the monthly amount she applies to it? debts interest rate minimum monthly payment debt 1 5.5% $75 debt 2 2.75% $250 debt 3 13.25% $150 a. debt 1, $225 b. debt 1, $375 c. debt 3, $300 d. debt 3, $400 at greenbrier bank, checking account customers earn 0.8% interest a month on their account balances, pay a $0.10 service fee per check, and pay a monthly $2.00 financial charge. calculate the income earned on the checking account for a customer who writes 21 checks and maintains a minimum balance of $1,210. a. $4.27 b. $5.58 c. $6.42 d. $7.35 which statement most accurately compares debit and credit cards? a. both cards deduct from funds currently in a checking account. b. both cards use funds temporarily loaned from a financial institution. c. both cards are processed by the same card system services. d. both carry the risk of overdraft.

Combined megan and kelly worked 60 hours. kelly worked twice as many hours as megan. how many hours did they each worked?

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.