The solar array panels on the outside of the International Space Station are about 240 feet long by 40 feet wide. What is the area of the top face of one solar array panel? Show your work, including the formula used to solve the problem.

Area cover by solar panel to face = 9,600 feet²

Step-by-step explanation:

Given:

Length of Solar panels = 240 feet

Width of Solar panels = 40 feet

Find:

Area cover by solar panel to face

Computation:

Area of rectangle = Length × Width

Area cover by solar panel to face = Length of Solar panels × Width of Solar panels

Area cover by solar panel to face = 240 × 40

Area cover by solar panel to face = 9,600 feet²

Area cover by solar panel to face = 9,600 feet², The panels are about 340 feet Long, and 40 feet Wide. The area of this rectangle is a Length x Width.

Step-by-step explanation:

I don't really know if this helps, but If you use it change some words since this is what I wrote, or because we might have the same school districts, I don't want any trouble.. But if you need help understanding a bit more, ask me! ^.^

If this does help: Your welcome, bubs <3

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db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)