How many moles of oxygen atoms are in 2.000 x 10^15 molecules of sulfur dioxide (SO2)?

6.64*10^(-9) moles of oxygen.

Step-by-step explanation:

If we have N molecules, the number of moles is given by:

n = N/Nₐ

where Nₐ is the Avogadro's number:

Nₐ = 6.02214076*10^23

In 2.000*10^15 molecules of sulfur dioxide, we have:

n = (2.000*10^15)/(6.02214076*10^23) = 3.32*10^(-9) moles of sulfur dioxide.

Now, sulfur dioxide has two oxygens and a single sulfur.

Then a mole of sulfur dioxide has two moles of oxygen and a single mol of sulfur.

Then in 3.32*10^(-9) moles of sulfur dioxide, we have twice that amount moles of oxygen, or:

2*3.32*10^(-9) = 6.64*10^(-9) moles of oxygen.

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560