Learning Task I. Using a piece of paper, follow the instructions below.

1. Draw a triangle and name it as ∆BOD

2. Put point Y on the right side of the triangle.

3. Extend line segment OD to point Y.

4. Identify the exterior angle of the triangle and its two remote interior angles.

5. Now, cut the two remote interior angles and paste it on the exterior angle.

6. Observe.

Please help me ​

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.

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step-by-step explanation: