The figure below shows the ideal pattern of movement of a herd of cattle, with the arrows showing the movement of the handler as he moves the herd. The arc the handler makes from the starting point to the return point should be a quarter of a circle: A sector showing a quarter of a circle is drawn. The radius is marked as 85 feet. The endpoints of the arc of the sector are ma Based on this theory, what distance will the handler move from the starting point to the return point if he creates an arc of a circle of radius 85 feet? (6 points) Group of answer choices 21.25 feet 133.45 feet

total of apples - take away four

6-4 = 2

answer is 2 apples

add me on g  

mail to get the anwser

blogan.20174

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

i think it would be c

mark brainliest if im right

step-by-step explanation: