Mathematics, 18.05.2021 19:20, morris9878

Suppose that a researcher, using data on class size (CS) and average test scores from third-grade classes, estimates the OLS regression + CS, = , SER = () () Construct a 95% confidence interval for , the regression slope coefficient. The 95% confidence interval for , the regression slope coefficient, is ( nothing, nothing). (Round your responses to two decimal places.) The t-statistic for the two-sided test of the null hypothesis : = is nothing. (Round your response to four decimal places.) Note: Assume a normal distribution. The p-value for the two-sided test of the null hypothesis : = is nothing. (Round your response to four decimal places.) Do you reject the null hypothesis at the % level? A. , because the p-value is than 0.01. B. , because the p-value is than 0.01. C. Yes, because the t-statistic is greater than 2.58. D. Yes, because the t-statistic is less than 2.58. The p-value for the two-sided test of the null hypothesis : = is nothing. (Round your response to four decimal places.) Without doing any additional calculations, determine whether is contained in the 95% confidence interval for . A. No, is not contained in the 95% confidence interval for . B. Yes, is contained in the 95% confidence interval for . The 99% confidence interval for is ( nothing, nothing). (Round your responses to one decimal place.)

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answered: Guest

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

answered: Guest

the results from a pre-test for students for the year 2000 and the year 2010 are illustrated in the box plot. what do these results tell us about how students performed on the 29 question pre-test for the two years?

if we compare only the lowest and highest scores between the two years, we might conclude that the students in 2010 did better than the students in 2010. this conclusion seems to follow since the lowest score of 8 in 2010 is greater in value than the lowest score of 6 in 2000. also, the highest score of 28 in 2010 is greater in value than the highest score of 27 in 2000.

but the box portion of the illustration gives us more detailed information. the middle bar in each box shows us that the median score of 20 in 2000 is greater in value than the median score of 17 in 2010. further, we note that the box and whiskers divide the illustration into four pieces. each of these four pieces represents the same portion of students. so, the upper half of the students in 2000 scored in the same score range as the upper one-fourth of the students in 2010, see the illustration at a score of 20.

by considering the upper one-fourth, upper half, and upper three-fourths instead of just the lowest and highest scores, we would conclude that the students as a whole did much better in 2000 than in 2010. we would conclude that as a whole the students in 2010 are less prepared than the students in 2000.

in this section, we discuss box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. the key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

step-by-step explanation:

answered: Guest

the solution is the point $(1,-3)$

step-by-step explanation:

we have

$3x-y=6$ > equation a

$y=x-4$ > equation b

adds equation a and equation b

$3x-y=6\\y=x--y+y=6+x-4\\3x=2+x\\3x-x=2\\2x=2\\x=1$

substitute the value of x in equation b to find the value of y

$y=(1)-4=-3$

the solution is the point $(1,-3)$

answered: Guest

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