Five applicants are to be scheduled for job interviews at five given times. On an application form, each applicant was asked to mark two out of the five times. What is the probability that each of them can be interviewed at one of the two times they have marked

0.01024

Step-by-step explanation:

Assume marking was done at random : Hence, each of the 5 time slots have equal Chamves of being marked ;

Number of time slots, n = 5

Required to mark, number of preferred timeslot x = 2

P(x) = 2 /5 = 0.4

Probability of 0.4 that an interviewee gets one of his preferred timeslot.

Probability that each of the 5 interviewees gets one of their preferred time slots :

Using the multiplication rule of independence :

0.4 * 0.4 * 0.4 * 0.4 * 0.4 = 0.4^5 = 0.01024

0.01024 * 100% = 1.024%

1/800 is the right answer

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: