What is an
equation of the line that passes through the points (-3, -1) and
(-6, 3)?

y = -4/3x + 2

Step-by-step explanation:

to find slope use m= y2-y1/x2-x1

m= 3-(-1)/-6-(-3)

m= 4/-3

m= -4/3

then use point slope formula (y-y1) =m(x-x1)

(y-(-1)) = -4/3(x-(-3))

simplify

y+1 = -4/3x + 3

turn into slope intercept form

y = -4/3x + 2

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above