The constraints of a problem are listed below. What are the vertices of the feasible region? X+y<_5
y<_3
X>_0
y>_0

(0, 0), (0, 3), (2, 3), and (5, 0)

Step-by-step explanation:

The constraints of the problem are:

x + y ≤ 5

y ≤ 3

x ≥ 0

y ≥ 0

Then:

Using the second and fourth inequalities we can write:

0 ≤ y ≤ 3

Knowing that the minimum value of y is 0, then if we replace that in the first equation we get:

x + 0 ≤ 5

x ≤ 5

While for the maximum value of y, y = 3, this inequality becomes:

x + 3  ≤ 5

x ≤ 2

Now, the vertexes are the points where both variables take one of their extremes.

Then, we have a vertex at (0, 0) because we have:

x ≥ 0

y ≥ 0

So this is the vertex when both x and y take the minimum value.

When y takes the maximum value y = 3, and x takes the minimum value x = 0, we have the vertex:

(0, 3)

When y takes the maximum value, y = 3, and x takes the maximum value, x = 2, we have the vertex:

(2, 3)

When y takes the minimum value, y = 0, and x takes the maximum value, x = 5, we have the vertex:

(5, 0)

Then the four vertexes are:

(0, 0), (0, 3), (2, 3), and (5, 0)

no not all of them.

step-by-step explanation:

some of them have a square base.

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: