The maximum walking speed S, in feet per second, of an animal can be modeled by the equation S = gL, where g = 32 ft/sec and L is the length, in feet, of the animal's leg. To the nearest
hundredth, how many times greater is the maximum walking speed of a giraffe with a leg length of 6
feet than a hippopotamus with a leg length of 3 feet?

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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step-by-step explanation:

p = 6s

step-by-step explanation: