A factory produces ball bearings whose diameters are meant to have a mean of 3\text{ mm}3 mm3, start text, space, m, m, end text. Suppose that the actual sizes are normally distributed with a mean of 3\text{ mm}3 mm3, start text, space, m, m, end text and a standard deviation of 0.2\text{ mm}0.2 mm0, point, 2, start text, space, m, m, end text. The overseers took a random sample of n=100n=100n, equals, 100 ball bearings to see if their mean diameter was significantly different than the target. The mean diameter of the ball bearings in the sample was \bar x=2.96\text{ mm} x ˉ =2.96 mmx, with, \bar, on top, equals, 2, point, 96, start text, space, m, m, end text. To see how likely a sample like theirs was to occur by random chance alone, the factory overseers performed a simulation. They simulated 757575 samples of n=100n=100n, equals, 100 diameters from a normal population with a mean of 3\text{ mm}3 mm3, start text, space, m, m, end text and standard deviation of 0.2\text{ mm}0.2 mm0, point, 2, start text, space, m, m, end text. They recorded the mean of the diameters in each sample. Here are the sample means from their 757575 samples:

your answer is b ^w^ hope i

answer:     true

step-by-step explanation:

step-by-step explanation:

we are given a graph for system of inequalities.

in order to write the system of inequalities for the given graph, we need to find the inequality for each of the line separately.

let us find the slope of dotted line first.

taking two coordinates on the graph.

let us say (0,0) and (3,1).

let us find the slope of the line now.

slope of the dotted line would be =.

y-intercept of dotted line is y=0 only.

plugging slope m= and b=0 in slope-intercept form y=mx+b, we get

.

the line is shaded up of that dotted line.

therefore, for shading up we would take greater than inequality symbol > .

and because it's a dotted line we would take only > symbol in place of = sign in above equation of line.

therefore, inequality for dotted line would be

let us take two points (3,1) and (0,4) on the solid line.

slope of the solid line would be =.

for the solid line we have y-intercept b= 4.

plugging slope m= -1 and b=4 in slope-intercept form y=mx+b, we get

y = -1x + 4.

the line is shaded down of that solid line.

therefore, for shading down we would take less than inequality symbol < .

and because it's a solid line we would take ≤ symbol in place of = sign in above equation of line.

therefore, inequality for solid line would be

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497