A room measures 15 ft by 20 ft by 10 ft. If a basketball has a diameter of 9.6 inches, approximately how many basketballs will be needed to fill the room?

10344.827586 basketballs

Step-by-step explanation:

A room measures 15 ft by 20 ft by 10 ft. If a basketball has a diameter of 9.6 inches, approximately how many basketballs will be needed to fill the room?

Step 1

We find the volume of the room

The room is rectangular in shape

Volume = Length × Width × Height

= 15ft × 20ft × 10ft

= 3000ft³

Step 2

Basket ball is spherical in shape

Volume of a sphere = 4/3πr³

Diameter = 9.6 inches

Radius = Diameter/2 = 9.6 /2 = 4.8 inches

Convert Radius from inches to ft

= 4.8inches/12

= 0.408333 feet

Volume of a sphere = 4/3 × π × 0.408333³

= 0.29 ft³

Step 3

3000 ÷ 0.29

10344.827586

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

step-by-step explanation:

graph using a few selected

x         y

-1       15

0         6

1         2.4

2       0.96