PLEASE HELP WITH ANSWER ITS DUE TOMORROW

A: 46 meters at 3 seconds

B: 0 meters at 6.033 seconds

C. It depends where the tree is

D. 6.033 seconds

Step-by-step explanation:

A. To find max height, we need to find the vertex.

We can do this by using vertex from y=a(x-h)+k for y=a^2+b^2+c^2

h(t) = -5t^2+30t+1

h(t)+45 = - 5x^2+30x+45+1

h(t)+45= -5(x^2-6x-9)+1

h(t)+45 = -5(x-3)^2+1

h(t) = -5(x-3)^2+46

Hence, the max height is 46 at 3 seconds

B. The minimum height is 0 meters because of the problem

C. It depends because the parabola intersects x=10 in 2 places meaning that you need the tree to be in either of these two places to intercept the horseshoe

D. -5x^2+30x+1=0

     5x^2-30x-1=0

     x=  (30+-sqrt(30^2-4*5*-1))/2*5

     x=(30+-sqrt920)/10

     x=3+-2sqrt230/10

     x=3+-sqrt230/5

      This means that x =  -0.033  or 6.033. Negative value doesn't make sense so it's 6.033 seconds  

10 - 75

step-by-step explanation:

there's nothing attached so it's most likely anything in that range.

sina-sinb

cosb+cosa

tana-tanb

cos0+cos x pi/3

20tan

step-by-step explanation: