Can anyone help? I’ll give Thank you :)

Explanation:

f(x) is equal to both x^2-2x+3 and also -6x at the same time. Set those two expressions equal to one another and solve for x.

x^2-2x+3 = -6x

x^2-2x+3+6x = 0

x^2+4x+3 = 0

(x+3)(x+1) = 0 see note below

x+3 = 0 or x+1 = 0

x = -3 or x = -1

Note: 3 and 1 multiply to 3, and also add to 4.

Once we get the x values, we plug them into either equation to find the y value.

So if x = -3, then

f(x) = x^2-2x+3

f(-3) = (-3)^2-2(-3)+3

f(-3) = 9 + 6 + 3

f(-3) = 18

or we could say

f(x) = -6x

f(-3) = -6(-3)

f(-3) = 18

Both versions produce the same output when x = -3.

The second version is easier to work with.

Since x = -3 leads to y = 18, we know that (-3, 18) is one of the solutions. That explains where your teacher got (-3, 18) from.

We'll use this idea for x = -1 now

f(x) = x^2-2x+3

f(-1) = (-1)^2-2(-1)+3

f(-1) = 1 + 2 + 3

f(-1) = 6

or we could say

f(x) = -6x

f(-1) = -6(-1)

f(-1) = 6

Like before, both versions of f(x) produce the same output when the input is x = -1.

The other solution is (-1, 6)

answer:  

step-by-step explanation:

odd numbers are only divisible by 1 and itself.

even numbers are divisible by more than 1 and itself.

for example 6 is even because it is divisible by more than 1 and its self. 1 x 6= 6 ; 2 x 3= 6

and 7 is odd because only 7 x 1 equals seveb

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.