А N
O
H
B
P
H Н
R
A
D
1
B.
E
D
2
T
A
M
B
todoro
P
A
U
V
P
L
N
F
T
A
Z
P
C С
M
W
E
1
G
S
B В
Q
R
T
A
Х
Y
D
M
1
L
T
M
A
U
V
L
S
B
K
L
N
E
L
E
G
z
K
S
F
L
N
N
M
L
А
G
J
H
K
S
D
F
T
A
P.
D
R
I
I
R
R
U
N
D
E
х
L
E
1
P
L
K
D
х
H
1
D
B
А
B.
H
R
P
G
E
1
N
A
R
M
Y
T
х
A
w
K
U
B В
U
N
M
G
P
S
D
F
H
G
K
J
C
1
A
L
A
R
M
O
M
E
A
S
W
N
J
F
D
S
O
T
S
O
H
w
O
H
A
E
K
T
M
​

Stop Spamming

ok

Step-by-step explanation:

goog may have it for you

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2