A company has offices in two different countries. Suppose that the average age (in years) of the employees at location A is 40.0 with a standard deviation of 5.5, and the average at location B is 36.0 with a standard deviation of 6.3. Every month, the company takes separate random samples of 50 employees from location A and 75 from location B for a survey. Each time, they look at the difference in the mean age sampled from each location (TA - B) What are the mean and standard deviation (in years) of the sampling distribution of TA TB? Choose 1 ​

answer: idk wbu

step-by-step explanation:

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130

the five is the numerator