Mhanifa please help. Find x

For the first

Since the angles in a triangle sum up to 180.

We already have angleA 41° and angleC 90°

To get the remaining angle B 180-(41+90)=49°

Now

We apply sine rule to solve

Divide each term you pick by the Sine of the angle directly opposite it.

So We have

4/Sin41° = X/Sin49

Making X subject..

X= 4Sin49/Sin41

X=4.601

To the nearest tenth

X= 4.6.

For the second question

Applying the same concept

Angle B = 180-(90 + 47) = 43°

Applying Sine Rule

X/Sin43 = 3/Sin90

Making x subject

X= 3Sin43/Sin90

X=2.04

To the nearest Tenth

X=2.0

#1

#2

damm bro the struggle

step-by-step explanation:

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.