Find the sum of the 1st 100 terms: 100+98+96+

First we Check if its an AP or GP

Its an AP because the Second term Minus the First term is = to 3rd term Minus Second term

Since it said "Sum"

The formula we should think Of is

Sn = n/2[2a + (n-1)d]

n=100

a(First term) =100

Common difference 'd' = Second term - First term or Third term - Second term

So

d= 98-100 or 96-98

d=-2.

Applying the Formula...

Sn = 100/2 [2(100) + (100-1)(2)]

Sn = 50[200 + (99)(2)]

Sn= 50[200 + 198]

Sn = 50[398]

Sn = 19,900.

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

add the table and i will answer correctly

step-by-step explanation: