A 50 foot ladder is set against the side of a house so that it reaches up 48 feet. If Mila grabs the ladder at its base and pulls it 6 feet farther from the house, how far up the side of the house will the ladder reach now? (The answer is not 42 ft.) Round to the nearest tenth of a foot.

~31.3

first use the pythagorean theorem. a^2+(40)^2=50^2.

simply. a+1600=2500. subtract 1600 from both sides. a^2=900.

square root both sides to get a= 30

then find how far the top of the ladder is from the ground once in its new position.

a^2+(39)^2=50^2.

simplify. a^2+1512=2500. subtract 1512 from both sides to get a^2=979.

square root both sides to get a=31.288975. round to the nearest tenth to get a=31.3

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100