In a game, four cards are labeled W, X, Y, and Z. Three tiles are numbered 3, 4, or 5. Two discs
are green and yellow. A player randomly
selects one card, one tile, and one disc.
Find the probability the player selects a card X
or Y, one tile 4 or 5, and green disc?

no not all of them.

step-by-step explanation:

some of them have a square base.

step-by-step explanation:

answer: i don't understand it

step-by-step explanation: sorry

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560