THINKING/INQUIRY: Show all of your work and explain fully. Include a sketch of your graph as well.
Determine a quartic function, f(x), with the following conditions:
• f(-3) = 16,f(3) = 0 and f(-1) = 0
The y-int is 2.
. f(x) > 0, when x < 3
• f(x) < 0,when x > 3

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

3 qrs + 3/2 xy hope this : /

step-by-step explanation: