X2 – 7x + 6 = -8
solve using factoring

Step-by-step explanation:

Rewrite this in standard quadratic equation form:  x^2 - 7x +  6 + 8 = 0, or x^2 - 7x + 14 = 0.  This does not factor easily, so I will use the quadratic formula to find the roots and then write out the factors based upon the roots:

The discriminant is b^2 - 4ac, which here is (-7)^2 - 4(1)(14) = -7.

Because the discriminant is negative, we know that there are two unequal, complex roots.  They are:

      -(-7) ± i√7         7 ± i√7

x = =

              2                     2

One factor is (x - [1/2]{7 ± √7}  )

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

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