Hey!! Can any of y'all help me find the center and radius of this equation?

x^2+y^2-8x+2y=-8

Center: (4,-2)

Radius: 2√3 units

Step-by-step explanation:

We wish to find the center and radius of the equation x²+y²-8x+2y=-8

Step 1: Complete the square for both variables:

x²+y²-8x+2y=-8

x²-8x+y²+2y=-8 (Rearrange)

x²-8x+16+y²+2y+4=-8+16+4 (Add to both sides)

(x-4)²+(y+2)²=12 (Reduce trinomials)

Step 2: Interpret the center and radius of the circle:

The equation of a circle is (x-h)²+(y-k)²=r² where (h,k) is the center of the circle and r is the radius of the circle. Since (h,k) translates to (4,-2), this means the center of the circle is (4,-2). Since r²=12, then r=√12=2√3 units

0 is its x and y coordinate

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: