What is the equation of the line that passes trough point (6,-5) and has a slope of -3/2

The slope-intercept form of the equation of a line is y = mx + b, where m is the slope of the line, and b is the y-intercept. Given, Slope = m = -4. And line passes through the point (-6,5). we get y=mx+b => 5 = -4(-6)+b => b = 5-24 => b=-19.

Step-by-step explanation:

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step-by-step explanation:

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value