Mathematics, 14.05.2021 16:20, lopezjose1530

Triangle D E F is shown. Angle D E F is 90 degrees and angle F D E is 42 degrees. The length of D E is 7.2 and the length of E F is d. What is the value of d to the nearest hundredth?

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answered: sleimanabir

The value of the d is 6.48

Step-by-step explanation:

The value of the d is 6.48, if the angle D E F is 90 degrees and angle F D E is 42 degrees and the length of D E is 7.2 and the length of E F is d.

Step-by-step explanation:

The given is,

Angle D E F is 90 degrees

Angle F D E is 42 degrees

The length of D E is 7.2

The length of E F is d

Step:1

For the given values,

Triangle DEF is right angle triangle,

Ref the attachment,

Angle FDE, ∅ = 42°

DE = 7.2

EF = d

Trigonometric ratio for the given right angle triangle,

∅ =

( the value of tan 42° = 0.900404 )

EF = d = 6.48

Result:

The value of the d is 6.48, if the angle D E F is 90 degrees and angle F D E is 42 degrees and the length of D E is 7.2 and the length of E F is d.

answered: Guest

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring). so find the distance between (1,2) and (4,2). that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3. it is a regular polygon which means all sides are congruent. you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

answered: Guest

central angle of a triangle has the same measure as its intercepted arc.

step-by-step explanation:

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Triangle D E F is shown. Angle D E F is 90 degrees and angle F D E is 42 degrees. The length of D E...