Emergency rooms have reason to suspect that visits increase on the weekends. A recent report indicates that Monday through Thursday represent 10% per day of the weekly total visits while Friday accounts for 15%, Saturday 25% and Sunday 20%. If your ER has the following pattern, Monday, 120, Tuesday, 130, Wednesday 110, Thursday 95, Friday 160, Saturday 280 and Sunday 105. Does your facility have the same pattern as the recent report at the 10% level

No the facility dose not have the same pattern as the recent report at the 10% level

Step-by-step explanation:

To determine if the Facility have the same pattern ; Perform Chi squared test for Goodness of fit

state the hypothesis

H0 : μ = same pattern

Ha : μ ≠ same pattern

expected frequency ( E )  = proportion * summation of frequency

summation of frequency = 1000

degree of freedom = 7 - 1 = 6

Next : Calculate the expected frequency (E) , (O-E)²/E.  given that the observed frequency  and expected proportion is given

For Monday

expected frequency = proportion * frequency = 0.1 * 1000 = 100

(O-E)²/E.  = ( 120 - 100 )^2 / 100 = 4.0.

observed frequency ( O ) ,  expected frequency  ( E )

For Tuesday

E = 0.1 * 1000 = 100

(O-E)²/E  = ( 130 - 100 )^2 / 100 = 9.0

Repeat same calculations for Wednesday through Sunday

Then perform Chi-squared test

X² = Σ(O-E)²/E  = 63.642    

∝ = 0.1

df = 6

hence P-value = 0.000 ( =chisq.dist.rt(test-stat,df)

since P-value < ∝ ; we will fail to reject Ha  hence we reject H0

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

goog may be able to you find that answer