Philip has already run 21 miles on his own, and he expects to run 1 mile during each track practice. How many track practices would it take for Philip to run 41 miles?

20

Step-by-step explanation:

21 has already been ran,so subtract that from 41. If he runs 1 mile per track,20 more practices. (41-21)

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2